4l^2+4l-3=(2l-1)(2l+3)

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Solution for 4l^2+4l-3=(2l-1)(2l+3) equation: 



4l^2+4l-3=(2l-1)(2l+3)

We move all terms to the left:

4l^2+4l-3-((2l-1)(2l+3))=0

We multiply parentheses ..

4l^2-((+4l^2+6l-2l-3))+4l-3=0



We calculate terms in parentheses: -((+4l^2+6l-2l-3)), so:

(+4l^2+6l-2l-3)

We get rid of parentheses

4l^2+6l-2l-3

We add all the numbers together, and all the variables

4l^2+4l-3

Back to the equation:

-(4l^2+4l-3)



We add all the numbers together, and all the variables

4l^2+4l-(4l^2+4l-3)-3=0

We get rid of parentheses

4l^2-4l^2+4l-4l+3-3=0

We add all the numbers together, and all the variables

=0

l=0/1

l=0

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